Kinetics Speed by a component

@damiryagudin if we are talking about an irreversible reaction, is it possible to calculate its rate by increasing the concentration of the product?

@argentum You can calculate it, but the speed will not change. It won't be right. If you want to increase the concentration of the product, then you first need to increase the concentration of the reagent. After that, the reaction rate can be calculated, assuming that the concentration of the reaction product has increased. Again, everything is not so simple here, there may be losses of both the reagent and the product. If this is not taken into account, then how much will this calculation be correct? It remains only to compare. Whether it is justified to calculate the reaction speed in this way is a big question.

I would rather advise calculating the rate of a chemical reaction through the kinetic equation of a chemical reaction (the law of acting masses).

@damiryagudin yes, it’s understandable, it’s just not completely clear why it’s impossible for products

@damiryagudin I understand that you are talking about chemical equilibrium here

@argentum We can determine the reaction rate by the differential method from the kinetic curve of the reaction product, as the angular coefficient to the tangent at the selected point. But such a graphical method is less accurate. And it makes no sense to use this method, finding only the velocity from the kinetic curve of the reaction product, since you will not find either the reaction order or the velocity constant. Yes, if of course you use the kinetic curve of the reagent, then you can already determine.

@argentum I will tell you more that in order to determine kinetic regularities, the reaction order and the reaction constant are mainly calculated, from which the activation energy can be found, and not as such the reaction rate. These are important kinetic parameters. I really hope that I have explained enough from the position of finding the reaction rate through the concentration of reaction products and that you have understood me.

But I'm talking about the true speed.

@damiryagudin Is this method less accurate precisely because of the methodology of the calculations themselves?

@damiryagudin Thanks, thanks for the detailed explanation.

@argentum Yes that's right.